BiancaMarie3942 BiancaMarie3942
  • 01-08-2018
  • Physics
contestada

What is the angular momentum of a 3.2-kg uniform cylindrical grinding wheel of radius 27 cm when rotating at 1500 rpm ?

Respuesta :

aristocles aristocles
  • 08-08-2018

Angular momentum is given by

[tex]L = I w[/tex]

here we have

I = moment of inertia of wheel

[tex]I = \frac{1}{2}mR^2[/tex]

[tex]I = \frac{1}{2}*3.2*0.27^2[/tex]

[tex]I = 0.117 kg*m^2[/tex]

angular speed is given as 1500 rpm

[tex]w = 2 \pi f[/tex]

[tex]w = 2 *\pi * \frac{1500}{60}[/tex]

[tex]w = 157 rad/s[/tex]

now angular momentum is given by

[tex] L = 0.117 * 157 = 18.4 kg*m^2* rad/s[/tex]

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