Evaluate -u2v3 when u=4 and v=-2

Question

03-04-2016
Mathematics

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Evaluate -u2v3 when u=4 and v=-2

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tippytoe14 tippytoe14 · Answer 1 · 2016-04-03T19:53:36+02:00

tippytoe14 tippytoe14

03-04-2016

First lets substitute the values: -4x2x-2x3

Now lets solve: -4 times 2 is -8. Now -8 times -2 is 16 because a negative times a negative is a positive. The last step is to do 16 times 3 which is forty-eight.

Final Answer: When u=4 and v=-2 the equation is 48.

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