lindareyes88575 lindareyes88575
  • 03-04-2019
  • Mathematics
contestada

find the vertex for the function
[tex]g(x)=2x^{2} +12-16[/tex]

Respuesta :

MrSmoot MrSmoot
  • 03-04-2019

Answer:

(-3, -34)

Step-by-step explanation:

I'm assuming g(x) is supposed to by g(x) = 2x² + 12x - 16

The general form for a quadratic function is f(x) = ax² + bx + c

For our equation, a = 2, b = 12 and c = -16

The formula for the x coordinate of the vertex is

x = -b/(2a)

Plug in our values and simplify...

x = -12/(2*2) = -12/4 = -3

Plug that value into g(x) to find the y coordinate of the vertex:

g(-3) = 2(-3)² + 12(-3) - 16

  g(-3) = 2(9) - 36 - 16

     g(-3) = -34

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