jccrowson21 jccrowson21

04-01-2021
Mathematics

contestada

Solve the system of equations: y = 2x - 5, y=x^2- 5
A. (0, -5) and (2, - 1)
B. (0,5) and (2, 2)
C. (-1,-4) and (3, 4)
D. (-1.-7) and (4,3

Solve the system of equations y 2x 5 yx2 5 A 0 5 and 2 1 B 05 and 2 2 C 14 and 3 4 D 17 and 43 class=

Respuesta :

masbrosur masbrosur

04-01-2021

Answer:

A

Step-by-step explanation:

both equation is y so

2x - 5 = x² - 5

2x = x²

0 = x² - 2x

0 = x(x-2)

x = 0

x = 2

for x = 0

y = 2x - 5

y = 0 - 5

y = -5

(0,-5)

for x = 2

y = 2x - 5

y = 2(2) - 5

y = -1

(2,-1)

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