Respuesta :

wizard123
First lets review property of exponents:
[tex](a^m)^n = a^{m*n}[/tex]
[tex](\frac{a}{b})^m = \frac{a^m}{b^m}[/tex]
[tex]a^m *a^n = a^{m+n}[/tex]
[tex]a^{-m} = \frac{1}{a^m} [/tex]
[tex]a^0 = 1[/tex]

Ok now we can do this problem:
[tex](2^{8(-2)} * 3^{(-5)(-2)}*1^{-2}) \frac{3^{(-2)(4)}}{2^{3(4)}} * 2^{28}[/tex]
[tex](2^{-16} *3^{10}*1)(\frac{3^{-8}}{2^{12}})*2^{28}[/tex]
[tex](2^{-16 -12+28}) (3^{10 -8})[/tex]
[tex](2^0)(3^2)[/tex]
[tex]= 9[/tex]

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