babyygiggs
babyygiggs babyygiggs
  • 04-03-2017
  • Mathematics
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Find the zeros. g(x)=(x^2+4x-12)(x-3)

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Setor9
Setor9 Setor9
  • 04-03-2017
g(x)=(x^2+4x-12)(x-3)
=(x+6)(x-2)(x-3)
=x+6 = 0
-6 -6
x=-6

x-2 = 0
+2 +2
x=2

x-3 = 0
+3 +3
x=3
The zeros are {-6, 2, 3}
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