reinpimentelp2jzi8 reinpimentelp2jzi8

04-04-2018
Mathematics

contestada

solve for h in the formula V=1/3rh

Respuesta :

asiafloren asiafloren

04-04-2018

h=3v/r should be your answer have a nice day,evening, night

Answer Link

04-04-2018

to solve for h you need to isolate it

3v/a=h

Answer Link

Otras preguntas

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

find the circumference of a circle whose radius is 15.4cm

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

jasmines cd collection is 3/8 jazz 1/4 rap and the rest is rock music what is the fraction of rock music

What value of x makes the equation true ? 4(2x-4)=16

find the circumference of a circle whose radius is 15.4cm

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})