jasminph9567 jasminph9567
  • 02-05-2018
  • Physics
contestada

If a spaceship of proper length 40 m is measured to have a length 30 m, how fast is it moving?

Respuesta :

skyluke89
skyluke89 skyluke89
  • 12-05-2018
In special relativity, the length contraction of an object moving with speed v is given by
[tex]L=L_0 \sqrt{1- \frac{v^2}{c^2} } [/tex]
where
L is the measured length
L0 is the proper length
v is the speed of the object
c is the speed of light

In our problem, the measured length is 30 m while the proper length was 40 m, therefore if we re-arrange the equation we can calculate the speed of the spaceship:
[tex]v=c \sqrt{1- (\frac{L}{L_0})^2 }=(3 \cdot 10^8 m/s ) \sqrt{1-( \frac{30m}{40 m} )^2}=1.98 \cdot 10^8 m/s [/tex]
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